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CBSE Class 10 Answered

Answer the following
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Asked by tultuldutta58 | 08 Jan, 2018, 03:34: AM
answered-by-expert Expert Answer

t9=a+8d=499..............eq.(1)

t499=a+498d=9............. eq. (2)

On subracting eq. (2) from (1)

—490d=490 => d= —1

subs. 'd= —1' in eq. (1)

a + 8(—1)=499 => a=499+8=507

tn=a + (n—1)d

t508= a+( 508—1)d = a+507(d)= 507+507(—1)=>507—507=0

Answered by Arun | 08 Jan, 2018, 08:21: AM

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