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CBSE Class 10 Answered

answer question 1
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Asked by Trisha Gupta | 06 Sep, 2021, 10:47: AM
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If space triangle 1 space is space similar space to space triangle 2 fraction numerator perimeter space of space triangle 1 over denominator perimeter space of space triangle 2 end fraction equals fraction numerator side space of space triangle 1 over denominator side space of space triangle 2 end fraction 25 over 15 equals 9 over straight x straight x equals fraction numerator 9 cross times 15 over denominator 25 end fraction equals 5.4 cm
Answered by Arun | 07 Sep, 2021, 12:08: PM

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