An electric dipole moment 4x10^-9 cm is aligned at 30°with the direction of a uniform electric field of magnitude 5x10^4 NC^-1.calculate the magnitude of the torque acting on the dipole? 

Asked by mayaunni486 | 6th Jul, 2020, 11:26: AM

Expert Answer:

D i p o l e space m o m e n t comma space p space equals space 4 cross times 10 to the power of negative 9 end exponent space C. m
E l e c t r i c space f i e l d comma space E space space equals space 5 cross times 10 to the power of 4 space N divided by C space
theta space equals space 30 degree
T o r q u e space i s space g i v e n space b y comma space
tau space equals space p space cross times E with rightwards arrow on top space equals space p E space sin theta space
space equals space 4 cross times 10 to the power of negative 9 end exponent cross times 5 cross times 10 to the power of 4 cross times sin space 30 degree space equals space 10 to the power of negative 4 end exponent space N m
 
Thus, magnitude of the torque acting on the dipole is 10-4 Nm 

Answered by Shiwani Sawant | 6th Jul, 2020, 02:25: PM