after 5 years,Father's age will be thrice of his son.Five years ago, his age was seven times more than his son. What are their present ages?

Let the present age of son and father be x and y respectively. After 5 years, Son's age = x + 5 Father's age = y + 5 By given condition, y + 5 = 3x + 15 (1) Five years ago, Son's age = x - 5 Father's age = y - 5 From the given condition, y - 5 = 7x - 35 (2) Subtracting (2) from (1), 4x = 40 So, x = 10 Hence, present age of son = 10 Present age of father = 40