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after 5 years,Father's age will be thrice of his son.Five years ago, his age was seven times more than his son. What are their present ages?
Asked by Pratiksha Kanhe | 19 Dec, 2011, 12:00: AM
Let the present age of son and father be x and y respectively. After 5 years, Son's age = x + 5 Father's age = y + 5 By given condition, y + 5 = 3x + 15 (1) Five years ago, Son's age = x - 5 Father's age = y - 5 From the given condition, y - 5 = 7x - 35 (2) Subtracting (2) from (1), 4x = 40 So, x = 10 Hence, present age of son = 10 Present age of father = 40
Answered by | 19 Dec, 2011, 09:20: PM

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