CBSE Class 11-science Answered
A sample of water gives an analysis 6.8 mg/L of CaSO4, 3.65mg/L of Mg(HCO3)2. Calculate the total hardness and permanent hardness
Asked by mayuresh.sudrik | 25 Sep, 2023, 12:21: AM
Expert Answer
Dear Student,
Molar mass of CaCO3 = 100 g
Molar mass of CaSO4 = 136 g
Molar mass of Mg(HCO3)2 = 146 g
Hardness if expressed in CaCO3 equivalents,
CaSO4 = 6.8 x 100 / 136 = 5 mg / L
Mg(HCO3)2 = 3.65 x 100 / 146 = 2.5 mg / L
Temporary hardness (due to carbonates and bicarbonates) = 2.5 mg/L of Mg(HCO3)2
Permanent hardness = 5 mg/L of CaSO4
Answered by | 25 Sep, 2023, 09:30: AM
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