ICSE Class 10 Answered
A pully system with V.R. = 4 is used to lift a load of 175 kgf through a vertical height of 15m. The effort required is 50 kgf in the downword direction.(g= 10N/kg)
Calculate:
(1) Distance moved by the effort.
(2) work done by the effort.
(3) M.A. of the pully system.
(4) efficiancy of the pully.
Asked by Sanyajbp | 04 Mar, 2019, 05:11: PM
Expert Answer
Mechanical advantage = 175/50 = 3.5
Efficiency = (mechanical advantage/velocity ratio)×100 = (3.5/4)×100 = 87.5
Work done by effort = 50×10×(15/4)= 1875Joules
Distance moved by effort = 15/4 = 3.75 m
Answered by Ankit K | 04 Mar, 2019, 08:57: PM
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