ICSE Class 10 Answered
A nut can be opened by a lever 0.25 cm by applying a force of 80 N.What should be the length of lever, if a force of 32 N is enough to open the nut ?
Asked by nisha_vini29 | 16 May, 2016, 06:09: PM
Expert Answer
Hi,
The turning effect is the same in both the case
τ1 = τ2
Load × Lever arm = Load × Lever length
80 N × 0.25 × 10-2 = 32 × Lever length
Lever length = (80 N × 0.25 × 10-2) / 32
Lever length = 0.625 m = 62.5 cm
Answered by | 16 May, 2016, 06:38: PM
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