a floride of oxygen was prepared by mixing oxygen and flourine in the proper ratio.This compound cantains 32.1%flourine and 67.9%oxygen. what is the empirical formula of the compound? (at. wt of f =19 and o=16)
Asked by nileshpatel19752000
| 19th Sep, 2016,
06:05: PM
Expert Answer:
Solution:
Element
Percentage by mass
Relative Number of Moles
Simple Ratio of Moles
Simplest Whole Number Ratio
F
32.1
1 × 2 = 2
O
67.9
2.5 × 2 = 5
Simplest Whole number ratio is 2 : 5
Hence the empirical formula of compound is: O5F2
Solution:
|
Element |
Percentage by mass |
Relative Number of Moles |
Simple Ratio of Moles |
Simplest Whole Number Ratio |
|
F |
32.1 |
|
|
1 × 2 = 2 |
|
O |
67.9 |
|
|
2.5 × 2 = 5 |
Simplest Whole number ratio is 2 : 5
Hence the empirical formula of compound is: O5F2
Answered by Hanisha Vyas
| 19th Sep, 2016,
07:03: PM
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