A cricket ball of mass 100g strikes the hand of a player with velocity of 20m/s and is brought to rest in 0.01 s. calculate:(i)the force applied by the hands of player (ii)the acceleration of the ball
Asked by
| 3rd Nov, 2013,
04:12: PM
Expert Answer:
initial velocity(u) = 20m/s
final velocity (v) = 0m/s
mass of the ball(m) = 100g = 0.1kg
time (t) = 0.01s
We know, v = u + at
0 = 20 + a*0.01
a= -2000m/s2
F = m a
F = (0.1*(-2000)) = -200N
F = -200N and a = -2000m/s2
initial velocity(u) = 20m/s
final velocity (v) = 0m/s
mass of the ball(m) = 100g = 0.1kg
time (t) = 0.01s
We know, v = u + at
0 = 20 + a*0.01
a= -2000m/s2
F = m a
F = (0.1*(-2000)) = -200N
F = -200N and a = -2000m/s2
Answered by Faiza Lambe
| 3rd Nov, 2013,
10:18: PM
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