ICSE Class 10 Answered
a cell of E.M.F 1.5v and internal resistance 10 ohms is connected to a resistor of 5 ohms with an ammeter in series. draw a bircuit diagram of the arrangement and calculate: (1)ammeter reading (2) the potential differance across the 10ohms resistor
Asked by bharadwajlucky26 | 14 Sep, 2018, 04:53: PM
Expert Answer
Current in the circuit = 1.5 /(10+5) = 0.1A . Ammeter will show the reading 0.5 A
voltage drop across 5Ω resistance = 5×0.1 = 0.5 V
Answered by Thiyagarajan K | 15 Sep, 2018, 03:13: PM
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