A BULLET FIRED INTO A FIXED TARGET LOSES HALF OF ITS VELOCITY AFTER PENETRAATING 3 CM. HOW MUCH FURTHER IT WILL PENETRATE BEFORE CONING TO REST ASSUMING THAT IT FACES CONSTANT RESISTANCE TO MOTION.
Asked by deepika babbar | 18th Oct, 2013, 12:39: PM
The bullet loses half its velocity after penetrating 3 cm into the target.
Let us say that the gun fires the bullet with force F.
The work done by the gun goes as change in kinetic energy of the bullet.
Thus, work done after penetrating 3 cm inside the target is
F × (3 cm) = ½mv2 - ½m(v/2)2 = 3/8 mv2
Thus, we have
mv2 = 8F
Now, when the bullet penetrates further distance x, the entire kinetic energy is lost. Thus, we have
F × (3 + x cm) = ½mv2
Thus, the distance x further penetrated by the bullet inside the target is,
Answered by Romal Bhansali | 28th Oct, 2013, 09:55: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number