NEET Class neet Answered
a body of mass m is projected with u initial speed at angle theta with horizontal.change in momentum after time t
Asked by priyankaranijha2001 | 01 Feb, 2021, 19:17: PM
At t = 0 , Horizontal component of velocity = u cosθ
After time t , Horizontal componenet of velocity = u cosθ
At t = 0 , vertical component of velocity = u sinθ
After time t , vertical componenet of velocity = ( u sinθ ) - ( g t )
Let horizontal component is parallel to x-axis of cartesian coordinate system and
vertical component coincide with y-axis of cartesian system.
Momentum in vector form at t = 0 , Pi = m [ ( u cosθ )
+ ( u sinθ )
]
![begin mathsize 14px style i with hat on top end style](https://images.topperlearning.com/topper/tinymce/cache/a5a79159fc1a127cc872f245943c4834.png)
![begin mathsize 14px style j with overbrace on top end style](https://images.topperlearning.com/topper/tinymce/cache/0273e5e7da324d57925f226602a075ec.png)
Then momentum in vector form after time t , Pf = m [ ( u cosθ )
+ ( u sinθ - g t )
]
![begin mathsize 14px style i with hat on top end style](https://images.topperlearning.com/topper/tinymce/cache/a5a79159fc1a127cc872f245943c4834.png)
![begin mathsize 14px style j with overbrace on top end style](https://images.topperlearning.com/topper/tinymce/cache/0273e5e7da324d57925f226602a075ec.png)
Change in momentum ΔP = Pf - Pi = -m ( gt )
![begin mathsize 14px style j with overbrace on top end style](https://images.topperlearning.com/topper/tinymce/cache/0273e5e7da324d57925f226602a075ec.png)
Answered by Thiyagarajan K | 01 Feb, 2021, 20:38: PM
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