A ball dropped from the top of the tower falls first half of the heigth of the tower in 10 s.  find the total time spend by the ball in the air. take g = 10 m/s square.

Asked by Sayoni Maiti | 4th Jun, 2014, 10:19: AM

Expert Answer:

Let h be the height of the tower.
Given that at t= 10 sec , distance travelled =h / 2
Using the equation , S=ut + (1/2)at2
Here u =0 , a =10 m/s2 , t= 10 sec
S = 0 + (1/2) × 10×(10)2
S = 500 m
So half the height of tower = 500 m
i.e h/ 2 = 500 m
h = 500×2 m
h=1000 m
Total time taken by the ball can be determined by using the equation, S=ut + (1/2)at2
Here S =1000 m , t = ?
1000 = (1/2)×10×t2
t2 = 2000 / 10
t = 14.14 sec

Answered by Jyothi Nair | 4th Jun, 2014, 11:14: AM

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