Asked by baidshryans | 2nd Oct, 2008, 11:35: AM
let the diameter of cylinder be d.
then volume of the cylinder = pi*(d/2)2*d = pi*d3 /4
now diameter of the ball d' = d/2
volume of the balls = 4 * ( 4/3 pi (d'/2)3 ) = 16/3 pi (d/4)3 = pi*d3/12
the equal volume of the water will flow out which is pi*d3/12
which is 1/3 of the total water which was in the cylinder i.e. 33.33% water flow out.
Answered by | 3rd Oct, 2008, 03:51: AM
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