1.84 g mixture of CaCO3 and MgCO3 was heated to a constant weight till 0.96 g residue formed % MgCO3 in the sample was

Asked by Anil | 13th May, 2017, 09:53: PM

Expert Answer:

Let the mass of CaCO3 =xg ,so the mass of MgCO3 = 1.84-xg
x gram of CaCO3 will give CaO = 56 x /100
similarly 1.84 -x g will give MgO = 40(1.84 -x)/ 84 g
Total mass =0.96g
so, 0.56 + 40(1.84 -x)/ 84 g =0.96
x= 1
% of CaCO3 = 1/1.84 = 54.35
% of MgCO3 = 100- 54.35 = 45.65

Answered by Vaibhav Chavan | 15th May, 2017, 11:00: AM