CBSE Class 11-science Answered

Chemical reaction: CaCO₃ + 2HCl → CaCl₂  +  CO₂ + H₂O

Moles in 100 g CaCO₃ = 100 g / 100 g mol^-1 = 1 mol

Since molarity of a solution means the number of moles of solute in 1 litre of solution. The number of moles in 1 L, 1 M HCl = 1 mol

In the above reaction, for 1 mol of CaCO₃ we require 2 mol of HCl, but we have only 1 mol of HCl is a limiting reactant.

As 2 moles of HCl gives 1 mol of CO₂, 1 mol of HCl will produce = (1/2) x 1 = 0.5 mol of CO₂.

Hence, on complete reaction, 0.5 mol or 22 g (0.5 mol x 44 g mol^-1) of CO₂ will be obtained.