1 C of charge is contained in = 6.25 x 1018 electrons . explain how.
Asked by Rhea Babu | 12th Jul, 2013, 11:51: PM
we shall use the following relation for quantisation of electric charge
q = ne
where
q is the total charge, here it is 1 Coulomb
n is the number of electric charges (or electrons) carrying that total charge
and e is the electronic charge or 1.6 x 10-19 C
now, the number of charge carrying electrons will be
n = q / e
or
n = 1 / 1.6 x 10-19
thus, by solving further, we get
n = 6.25 x 1018 number of electrons which constitute 1 Coulomb of charge
we shall use the following relation for quantisation of electric charge
q = ne
where
q is the total charge, here it is 1 Coulomb
n is the number of electric charges (or electrons) carrying that total charge
and e is the electronic charge or 1.6 x 10-19 C
now, the number of charge carrying electrons will be
n = q / e
or
n = 1 / 1.6 x 10-19
thus, by solving further, we get
n = 6.25 x 1018 number of electrons which constitute 1 Coulomb of charge
Answered by | 13th Jul, 2013, 11:01: AM
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