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word problem??

Asked by 29th February 2008, 5:09 AM
Answered by Expert

an optically active compound 'A' C4H9Br, on reduction, gives optically inactive compound 'B'. 'A' on reaction with KOH(alc.) gives 'C' which on reaction with HBr gives 'A'  back. identify A,B and C and write the chemical reactions involved?

A  is CH3CH2CHBrCH3 will be optically active with the chiral carbon atom.


C isCH3CH=CHCH3 elimination will be by satzeffs rule.


Answered by Expert 20th December 2017, 4:22 PM
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