CBSE Class 11-science Answered

When 15g of a mixture of NaCl and Na2CO3 is heated with dil HCl, 2.5g of CO2 is evolved at STP. Calculate % composition of the original mixture.

Asked by PRIYA | 07 Jun, 2018, 12:28: PM

Expert Answer

N a C l space plus space H C l space rightwards arrow with blank on top space N o space r e a c t i o n space o c c u r s N a subscript 2 C O subscript 3 plus 2 H C l space rightwards arrow with blank on top space 2 N a C l space plus space C O subscript 2 space plus space H subscript 2 O N a C l space d o e s space n o t space r e a c t space w i t h space H C l comma G i v e n colon space M a s s space o f space C O subscript 2 equals space 2.5 space g M o l e s space o f space C O subscript 2 space equals space fraction numerator M a s s over denominator M o l. space w t. end fraction equals fraction numerator 2.5 over denominator 44 end fraction space equals space 0.056 space m o l e A f t e r space o b s e r v i n g space t h e space r e a c t i o n space i t space i s space f o u n d space t h a t comma 1 space M o l e space o f space N a subscript 2 C O subscript 3 space r e q u i r e d space t o space p r o d u c e space 1 space m o l e space o f space C O subscript 2 therefore space 0.05 space m o l e space o f space N a subscript 2 C O subscript 3 space r e q u i r e d space t o space p r o d u c e d space 0.05 space m o l e space o f space C O subscript 2 N o w comma space l e t s space f i n d space t h e space m o l e s space o f space N a subscript 2 C O subscript 3 comma space space space space space space M o l e s space o f space N a subscript 2 C O subscript 3 space equals fraction numerator M a s s over denominator M o l. space w t. end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 0.05 space equals fraction numerator m a s s over denominator 106 end fraction space space space space space space space space space M a s s space o f space N a subscript 2 C O subscript 3 equals 106 space cross times 0.05 space equals space 5.3 space g m N o w space a s space w e space h a v e space g i v e n space t h e space m a s s space o f space m i x t u r e space i s space 15 space g m therefore space M a s s space o f space N a subscript 2 C O subscript 3 space plus space M a s s space o f space N a C l space equals space 15 space g therefore M a s s space o f space N a C l space equals space 15 space minus space 5.3 space equals 9.7 space g T h e r e f o r e space percent sign space c o m p o s i t i o n space o f space N a subscript 2 C O subscript 3 space equals space fraction numerator 5.3 over denominator 15 end fraction cross times 100 space equals 35.33 space percent sign A n d comma space space percent sign space c o m p o s i t i o n space o f space N a C l space equals space fraction numerator 9.7 over denominator 15 end fraction cross times 100 space equals 64.66 space percent sign

Answered by Ramandeep | 08 Jun, 2018, 06:22: PM

CBSE Class 11-science Answered

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CBSE Class 11-science Answered

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