CBSE Class 11-science Answered
what volume of 0.2 M sulfuric acid is required to neutralize 25ml of 0.1 NaOH solution?

Asked by omniscientnjf2021 | 07 Apr, 2024, 22:18: PM
(M1V1) / n1 = (M2V2) / n2
(0.2 × V1) / 1 = (0.1 × 25) / 2
V1 = 6.25 ml
V1 = 12.5 ml
Answered by | 08 Apr, 2024, 10:07: AM
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