1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

# Trigonometry

Asked by 16th September 2009, 1:31 PM

We assume the following is the correct expression to be simplified.

[(1+sin2A)  +  (1-sin2A)] / [(1+sin2A) - (1-sin2A)]

Simplify using the following trignometric identities,

sin2 A + cos2 A = 1 and sin2A = 2sinAcosA

(1+sin2A) = (sin2 A + cos2 A + 2sinAcosA) = (sin A + cos A)2 = (sin A + cos A)

(1-sin2A) = (sin2 A + cos2 A - 2sinAcosA) = (sin A - cos A)2 = (sin A - cos A)

[(1+sin2A)  +  (1-sin2A)] / [(1+sin2A) - (1-sin2A)] =

[(sin A + cos A) + (sin A - cos A)] / [(sin A + cos A) - (sin A - cos A)] =

= tan A

Regards,

Team,

TopperLearning.

Answered by Expert 16th September 2009, 2:59 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10

### Free related questions

16th February 2017, 3:54 PM
15th February 2017, 11:50 AM
15th February 2017, 3:28 PM
RELATED STUDY RESOURCES :
CBSE Class-11-science QUESTION ANSWERS

### Latest Questions

IIT JEE Main Mathematics
Asked by vishakhachandan026 18th June 2019, 4:41 PM
CBSE X Biology Life Processes
Asked by geetajat301 18th June 2019, 4:28 PM