CBSE Class 11-science Answered
Trigonometry
Asked by | 16 Sep, 2009, 01:31: PM
Expert Answer
We assume the following is the correct expression to be simplified.
[(1+sin2A) + (1-sin2A)] / [(1+sin2A) - (1-sin2A)]
Simplify using the following trignometric identities,
sin2 A + cos2 A = 1 and sin2A = 2sinAcosA
(1+sin2A) = (sin2 A + cos2 A + 2sinAcosA) = (sin A + cos A)2 = (sin A + cos A)
(1-sin2A) = (sin2 A + cos2 A - 2sinAcosA) = (sin A - cos A)2 = (sin A - cos A)
[(1+sin2A) + (1-sin2A)] / [(1+sin2A) - (1-sin2A)] =
[(sin A + cos A) + (sin A - cos A)] / [(sin A + cos A) - (sin A - cos A)] =
= tan A
Regards,
Team,
TopperLearning.
Answered by | 16 Sep, 2009, 02:59: PM
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