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in exercise 1.3 1st q ii part abc is not subset of bcd but two elements are common i.e bc but in 2 question same exercise i part ab is subset of  bca how ??
Asked by parvanipatil09 | 29 Mar, 2024, 10:12: AM

Exercise 1, part (ii)

{ a, b } ⊄ { b, c, d  }

If Set-A is subset of  set-B , all elements of set-A is present in set-B

Element a of set { a, b } is not present in set { b, c , d } .

Hence { a, b } is not a subset of { b, c, d }

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Exercis 2 , part (i)

{a, b } ⊄ { b , c , a }

Above statement is false because {a,b} is a subset of {b,c,a} .

Both the elements a and b of { a, b } are present in {b,c,a} .

Hence , {a,b} is a subset of {b,c,a}

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Answered by Thiyagarajan K | 29 Mar, 2024, 01:24: PM

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