CBSE Class 11-science Answered
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Asked by nityaboragam | 11 Apr, 2024, 12:14: PM
let sinα = 1/2 and cosα = (√3 /2 ) so that tanα = 1/√3 and α = π/6
Hence above expression can be written as
cos( α - θ ) = - cos π
( α - θ ) = -π
( π/6 ) - θ = - π
θ = π + ( π/6) = ( 7 π ) /6
θ - ( π / 3 ) = [ ( 7 π ) /6 ] - [ ( 2 π ) /6 ] = ( 5 π ) /6
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Answered by Thiyagarajan K | 11 Apr, 2024, 15:12: PM
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