solve this - 3uusbx00

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solve this

Asked by surabhilakhara7299 | 24 Jun, 2021, 01:10: AM

Expert Answer

Vertical component of velocity u_y is determined from the folowing equation of motion

v² = u_y² - ( 2 g h )

where v = 0 is the velocity of ball at maximum height , g is acceleration due to gravity and h is maximum height

Hence we have ,

begin mathsize 14px style u subscript y space equals space square root of 2 space g space h end root space equals space square root of 2 cross times 9.8 cross times 39.2 end root space equals space 27.72 space m divided by s end style

Time taken to reach maximum height is determined from

v = u_y - ( g t ) or t = u_y / g = ( 27.72 / 9.8 ) = 2.83 s

Horizontal distance S travelled by the ball is determined from

S = u_x × t

where u_x is the horizontal component of velocity

u_x = S / t = 78.4 /2.83 = 27.72 m/s

Hence projection velocity of ball = u =

begin mathsize 14px style square root of u subscript x superscript 2 space plus space u subscript y superscript 2 space end root space equals space square root of 2 space cross times 27.72 space equals space 39.20 space m divided by s end style

Answered by Thiyagarajan K | 24 Jun, 2021, 08:58: AM

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