CBSE Class 11-science Answered
please answer this question
Asked by Suryavanshikatoch | 13 Feb, 2019, 11:25: AM
Expert Answer
Let the consecutive terms of G.P are : a/r , a , ar
product of three terms of G.P : (a/r)×a×(ar) = a3 = 1000 or a =10
by adding 6 to second term and 7 to third term, G.P becomes A.P. Hence terms of A.P are 10/r, 16, 10r+7
Hence we have 16 - (10/r) = (10r+7)- 16 or 16-(10/r) = 10r-9 .................(1)
aove eqn(1) is simplified as : 2r2 -5r +2 = 0 or (r-2)(2r-1) = 0
Hence r = 1/2 or 2
if we consider r=2, then terms of G.P., : 10/r, 10, 10r or 5, 10, 20
Answered by Thiyagarajan K | 13 Feb, 2019, 11:45: AM
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