Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

Permutation and combination

Asked by NikhilD 14th April 2010, 11:28 AM
Answered by Expert
Answer:

As we can see 8 are unmarried people, and 2 are married to each other, and since the married couple refuses to attend seperately, the total invitations are 9.

If the couple is excluded she has to select 5 people from 8, so 8C5

If the couple is included she has to select 3 people from 8, so 8C3.

Hence the total number of ways = 8C5 + 8C3 = 56 + 56 = 112.

Regards,

Team,

TopperLearning.

Answered by Expert 14th April 2010, 4:26 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!