CBSE Class 9 Answered
P is a point in the interior of a
parallelogram ABCD. Show that
(i) Area APB + Area PCD = area ABCD
(ii)
Area APD + Area PBC = area APB + area PCD
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
(i) Through point P draw a line parallel to AB.
Now, AXYB and XDCY are two parallelograms.
area APB + area PCD = (area AXYB + area XDCY)
area APB + area PCD = area ABCD …..(1)
(ii) Similarly, we draw a line MN parallel to AD through P.
Now, AMND and MNCB are two parallelograms.
area APD + area BPC = (area AMND + area MNCB)
area APD + area BPC = area ABCD …….(2)
Comparing (1) and (2),
area APB + area PCD = area APD + area BPC
Answered by | 04 Jun, 2014, 03:23: PM
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