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CBSE Class 9 Answered

P is a point in the interior of a parallelogram ABCD. Show that (i) Area APB + Area PCD = area ABCD (ii) Area APD + Area PBC = area APB + area PCD
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

(i) Through point P draw a line parallel to AB.

Now, AXYB and XDCY are two parallelograms.

area APB + area PCD = (area AXYB + area XDCY)

area APB + area PCD = area ABCD …..(1)

(ii) Similarly, we draw a line MN parallel to AD through P.

Now, AMND and MNCB are two parallelograms.

area APD + area BPC = (area AMND + area MNCB)

area APD + area BPC = area ABCD …….(2)

Comparing (1) and (2),

area APB + area PCD = area APD + area BPC

Answered by | 04 Jun, 2014, 03:23: PM

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