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CBSE Class 9 Answered

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Asked by Kchawla94 | 03 Jun, 2019, 08:02: PM
Expert Answer
Area of parallelogram ABCD = 84√3
DC × DE = 84√3
14h = 84√3
h = 7√3 = DE = BF
In ΔDEA
DE = √3/2 × AD
7√3 = √3/2 × AD
AD = BF = 14
Also
AE = 1/2 × AD = 7
In parallelogram ABCD,
AB = CD = 14 cm
DF = BE hence, 
AB = CD = 14
AE + BE = 14
7 + BE = 14
BE = DE = 7 
Area of EDFB = BE × DE = 7√3 × 7 = 49√3

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