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lim (a+h)2 sin (a+h) -a2 sin a / h

Asked by 11th June 2008, 8:43 PM
Answered by Expert
Answer:

Using sin(a+h)=sinacosh+cosasinh

lim(h-->0)       (   (a+h)2 sin (a+h) -a2 sin a)  /  h   = lim(h-->0)   (   (a+h)2sinacosh+(a+h)2cosasinh -a2 sin a ) /   h   

Siplifying and using sinh=h-h3/3! ...

The limit is equal to a2cosa.

Answered by Expert 10th December 2008, 9:27 PM
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