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keshav jump 6 feet on earth then how many long they jump on moon
Asked by sohanshingade10 | 24 Jun, 2023, 01:23: PM
answered-by-expert Expert Answer
Range R of distance in jumping is given by
 
begin mathsize 14px style R space equals space fraction numerator u squared sin 2 theta over denominator g end fraction end style
where u is initial speed , θ is initial angle of jumping direction above horizontal and g is acceleration due to gravity.
 
If initial speed u and initial angle θ are same on earth and moon, then the range R of jumping length is inversely proportional to acceleration due to gravity. 
 
Let ge is acceleration due to gravity on earth and gm is acceleration due to gravity on moon. 
 
ge = 9.8 m/s2   ;
 
gm = 1.625 m/s2 ;
 
Let Rm and Re are range of jumping distances on moon and earth res[ectively.
 
Then we have
 
begin mathsize 14px style R subscript m over R subscript e equals space g subscript e over g subscript m space equals space fraction numerator 9.8 over denominator 1.625 end fraction space almost equal to 6 end style
 
Then range Rm of jumping distance on moon = 6 × 6 m = 36 m
Answered by Thiyagarajan K | 24 Jun, 2023, 09:58: PM
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