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In given figure, PQL and PRM are tangents to the circle with centre O

at the points Q and R respectively. S is a point on the circle such

that SQL =50o and SRM=60o. Find the value of QSR.

Asked by Topperlearning User 7th February 2014, 2:50 PM
Answered by Expert
Answer:

In given figure, O is the centre of the circle.

Therefore, DOQL=DORM =90o

(radius is perpendicular to tangent at the point of contact)

DOSQ=DOQS= 90°-50°=40°

DRSO=DSRO=90°-60°=30°

Thus , DQSR = DOSQ+DOSR = 40°+30°=70°

Answered by Expert 7th February 2014, 4:50 PM
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