point A lies in the exterior of a circle with center P and radius 8 cm A tangent from A touches the circle at if AB=15 cm find PA

Asked by sinhkaran79 | 14th Mar, 2021, 12:59: PM

Expert Answer:

Given: AB = 15cm and Radius PB = 8 cm
As tangent is perpendicular to radius, so we have AB pis perpendicular to PB
So, triangle PBA is a right angled triangle at B
By Pyhtagoras theorem, we get
AP2 = PB2 + AB2 
       = 64 + 225
       = 289
Therefore, AP = 17 cm

Answered by Renu Varma | 15th Mar, 2021, 02:07: PM