point A lies in the exterior of a circle with center P and radius 8 cm A tangent from A touches the circle at if AB=15 cm find PA
Asked by sinhkaran79
| 14th Mar, 2021,
12:59: PM
Expert Answer:
Given: AB = 15cm and Radius PB = 8 cm
As tangent is perpendicular to radius, so we have AB pis perpendicular to PB
So, triangle PBA is a right angled triangle at B
By Pyhtagoras theorem, we get
AP2 = PB2 + AB2
= 64 + 225
= 289
Therefore, AP = 17 cm
Answered by Renu Varma
| 15th Mar, 2021,
02:07: PM
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