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CBSE Class 10 Answered

question
Asked by arindeep.singh | 02 Oct, 2020, 01:20: PM
Expert Answer
Question:
 
Solution:

Let TR = y

Since OT is perpendicular bisector of PQ.

Therefore, PR=QR=4cm

In right triangle OTP and PTR, we have,

TP2 = TR2 + PR2

Also, OT2 = TP2 + OP2

OT2 = (TR2+PR2) + OP2

(y+3)2 = y2 + 16 + 25  ... (OR = 3, as OR2 = OP2 - PR2)

 

6y=32

 y=

TP2=TR2+PR2

TP2=+42 = +16 

TP=  cm

Let TR = y

Since OT

is perpendicular bisector of PQ.

Therefore, PR=QR=4cm

In right triangle OTP and PTR, we have,

TP2=TR2+PR2

Also, OT2=TP2+OP2

OT2=(TR2+PR2) + OP2

(y+3)2=y2+16+25 (OR = 3, as OR2 = OP2 - PR2)

Answered by Renu Varma | 03 Oct, 2020, 04:08: PM
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