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how many grams of potassium chlorate should be decomposed to obtain 9.6 g of oxygen
Asked by nathsantanukumar | 30 Oct, 2018, 08:47: AM
answered-by-expert Expert Answer
The chemical equation for the decomposition of potassium chlorate,
 
space space 2 KClO subscript 3 subscript open parentheses straight s close parentheses end subscript space space space space space rightwards arrow with heat space on top space space 2 KCl subscript open parentheses straight s close parentheses end subscript space plus space 3 straight O subscript 2 open parentheses 2 cross times 122.5 close parentheses space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open parentheses 3 cross times 32 close parentheses 245.0 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 96 So space 96 space straight g space of space oxygen space is space produced space by space heating space 245 space straight g space of space KClO subscript 3 therefore 9.6 space straight g space space of space oxygen space will space be space produced space by space fraction numerator 9.6 cross times 245 over denominator 96 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 24.5 space straight g space of space KClO subscript 3
 
24.5 g of potassium chlorate is decomposed to obtain 9.6 g of oxygen.
Answered by Varsha | 30 Oct, 2018, 12:00: PM

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