CBSE Class 11-science Answered
Find the value of x+y if [x(1+3i)+y.(2-i)-5+i cube]=0
Asked by arshinhussain598 | 22 Mar, 2019, 07:47: PM
Expert Answer
I understand the question is : x(1+3i) +y(2-i) -(5+i)3 = 0 ;
f(x,y) = x(1+3i) +y(2-i) -(5+i)3 = 0 ........................(1)
we have (5+i)3 = 53 +15i ( 5+i ) +i3 = 125 + 75i +15 i2 + i3 = 125 +75 i -15 - i = 110 + 74 i
hence eqn.(1) is written as, x(1+3i) +y(2-i) - 110 - 74 i = ( x+ 2y -110 ) + i (3x -y -74) = 0 + i 0
By equating real and imaginary parts we get
x + 2 y = 110 .......................(2)
3 x + y = 74 .....................(3)
By solving eqns.(2) and (3) , we get x = 38/5 and y = 256/5 , hence x+y = 294/5 = 58.8
Answered by Thiyagarajan K | 23 Mar, 2019, 09:53: AM
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