CBSE Class 10 Answered
Experiment on refraction when light enters from rarer to denser, denser to rarer and in straight angle?
Asked by gsvjairam | 20 Aug, 2021, 08:26: PM
Expert Answer
(i) Let us take a clean glass slab , put it on a white paper that is placed on a cardboard.
Let us drw outline PQRS of glass slab as shown in figure.
(ii) Let us take 4 identical pins . Let us fix two pins at A and B as shown in figure so that pins are standing vertically.
(iii) let us view the pins at A and B through other side of glass slab and fix remaining pins at C and D so that
pins at and B are viewed in a line along C and D.
(iv) Now let us remove the glass slab, join the points A and B abd extend AB so that let ut meet the line PQ at O.
(v) Similarly join the points C and D and extend the line DC so that let it meet the line SR at O' .
(vi) Let us draw perpendicular line at O and O' as shown in figure.
(vii) Angle marked as i1 is angle of incidence at O . Angle marked as r1 is angle of refraction at O
(vii) Angle marked as i2 is angle of incidence at O' . Angle marked as r2 is angle of refraction at O'
(viii) Above procedure is repeated for different angle of incidence i1 by fixing pins at various position of A and B
In this experiment refraction is taking place at O when light travels from rarer medium (air) to denser medium (glass ).
It is found that refracted ray at O deviates from incident ray. The deviation is towards normal.
Similarly we see that refraction is taking place at O' when light travels from denser medium (glass) to rarer medium (air)
It is found that refracted ray at O' deviates from incident ray. The deviation is away from normal.
It can be found that the ratio sin(i1) / sin(r1) is a constant and this constant value is refractive index of glass with respect to air.
It can be found that the ratio sin(r2) / sin(i2) is a same constant as we get at the point O and
this constant value is refractive index of glass with respect to air.
Answered by Thiyagarajan K | 20 Aug, 2021, 10:44: PM
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