Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

please explain refraction through glass slab

 

Asked by nehchalrs15 | 05 Aug, 2020, 10:07: PM
Expert Answer

Consider a rectangular glass slab ABCD having parallel faces AB and CD as shown in above figure. A ray of light EF in air is incident on the glass surface AB at point O. As the ray EO enters from air (rarer medium) to glass (denser medium), the ray bends towards normal and follows the path OO' inside the glass slab. At point O', refraction takes place again. As the ray OO' enters from glass (denser medium) to air (rarer medium), the ray bends away from normal and follow the path O'H outside glass slab.

Here, the ray EF is called incident ray, OO', the refracted ray and O'H, the emergent ray.

As per the laws of refraction,  and.

The emergent ray O'H is parallel to the incident ray EF. The perpendicular distance O'L between the original path of incident ray and the emergent ray is called the lateral displacement.

Answered by Shiwani Sawant | 05 Aug, 2020, 11:31: PM
CBSE 10 - Physics
Asked by Trisha Gupta | 22 Nov, 2021, 01:03: AM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by burhanraja55 | 27 Oct, 2021, 03:40: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by chalamsimaha | 15 Feb, 2021, 08:37: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by arindeep.singh | 23 Sep, 2020, 09:08: AM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by nehchalrs15 | 05 Aug, 2020, 10:07: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by jonysin042 | 11 Jun, 2020, 08:46: AM
ANSWERED BY EXPERT
×