NEET Class neet Answered
Qn.#15
It is given that two equal fragments of mass m are moving perpendicular to each other with speed v .
Hence by momentum conservation , if the third fragment of mass 3m is moving with speed V then we have
Hence from above expression, we get , V = (√2/3) v
Total kinetic energy E after collision is
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Qn.#16
It is given that two equal fragments of mass m are moving perpendicular to each other with speed v .
Hence by momentum conservation , if the third fragment of mass 2m is moving with speed V then we have
V = v/√2
Total kinetic energy E is
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Qn.#17
If velocity of water in pipe is v , then length of water volume coming out of pipe is v .
If unit length of water volume has mass m , then mass of water volume coming out of pipe is ( m v )
Rate of kinetic energy = (1/2) ( mv ) v2 = (1/2) m v3