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 A train of mass 16800 Kg is pulled by its locomotive with a force of 10000 N and its speed increases from 10 ms-1 to 12 ms-1 in a distance of 50 m. Calculate the resistive force assumed constant in that distance.

Asked by sidharthsuperior 30th March 2022, 9:37 AM
Answered by Expert
Answer:
mass of train, m = 16800 kg 
 
u = 10 m/s 
v = 12 m/s
s = 50 m 
v2 - u2 = 2as 
122 - 102 = 2a(50) 
100a = 144 - 100 
a = 44/100 = 0.44 m/s2 
Thus, 
Force = mass x acceleration  
 = 0.44 x 16800 = 7392 N
Answered by Expert 30th March 2022, 10:22 AM
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