JEE Class main Answered
The posted image is not clear. Magnifying lens is used to read the question . I assume the question is as follows
Question :- A particle of mass 2 kg is subjected to force that varies with time as shown above. Particle is initially at rest.
What is the velocity of particle after 10 s ?
------------------------------------------------------------------------
Force F(t) during the period t=0 to t=2 s is
F(t) = ( 5 t )
Acceleration a(t) = force/mass = (5t)/2 = 2.5 t
acceleration a(t) = dv/dt = 2.5 t
velecity as a function of time from t=0 to t=2 s is determined by integrating above expression
dv = 2.5 t dt
v(2) - v(0) = 1.25 × 4 = 5 m/s
hence velocity at t =2 is v(2) = 5 m/s
-----------------------
Force F(t) during the period t= 2 s to t = 4 s is
F(t) = 10 N
Acceleration a(t) = force/mass = 10/2 m/s2 = 5 m/s2
acceleration a(t) = dv/dt = 5 m/s2
velocity as a function of time from t = 2 s to t = 4 s is determined from equation of motion " v(t) = v(2) + ( a × Δt ) "
where time interval Δt = (6-4) s = 2 s
v(t) = 5 + ( 5 × Δt )
velocity at t = 4 s is , v(4) = 5 + ( 5 × 2) m/s = 15 m/s
--------------------------------------------------------------------------
Force F(t) during the period t= 4 s to t = 6 s is
F(t) = 10 + (t-4)5 = 5t - 10
Acceleration a(t) = force/mass = 2.5 t - 5
acceleration a(t) = dv/dt = 2.5 t - 5
velocity as a function of time from t = 4 s to t = 6 s is determined by integrating above expression
dv = 2.5 t dt - 5 dt
v(6)-v(4) = 1.25 × (36-16) - 5 × (6-4) = 15 m/s
velocity at t = 6 s is , v(6) = ( 15 + 15 ) m/s = 30 m/s
--------------------------------------------------------------------------
Force F(t) during the period t= 6 s to t = 10 s is
F(t) = 20 - (t-6)5 = 50 - ( 5 t )
Acceleration a(t) = force/mass = 25 - (2.5 t )
acceleration a(t) = dv/dt = 25 - (2.5 t )
velocity as a function of time from t = 6 s to t = 10 s is determined by integrating above expression
dv = 25dt - (2.5 t dt )
v(10)-v(6) = 25(4) - 2.5(64) = 20 m/s
velocity at t = 10 s is , v(10) = ( 30+20 ) m/s = 50 m/s