JEE Class main Answered
Let us consider a particle motion with constant speed v . Hence particle position x with time t is given by
where xo is initial position .
Let us consider following data
Point | time (s) | position ( m ) |
A | 2 | 20 |
B | 4 | 30 |
C | 6 | 40 |
D | 8 | 50 |
E | 10 | 60 |
The above data is plotted as given below . The graph above data is linear or striaght line.
If we extend the line to meet y-axis , then the point of intersection of graph and y-axis is y-intercept.
In above graph , if we extend the graph to meet y-axis , we get y-intercept 10 m .
Hence at t = 0 ,position of particle is 10 cm .
To get slope of graph , let us fix two points on graph and draw right triangle so that line between two fixed points is
hypotenuse of right triangle . Then the ratio of value of vertical line to the value of horizontal line is slope .
In the above graph , let us fix point A and point C and draw the right triangle as shown in figure so that
line segment between A and C is hypotenuse.
Then slope = ΔS/Δt = [ (40-20) m / (6-2) s ] = 5 m/s