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Asked by myselfsnehu5577 | 29 Nov, 2023, 13:19: PM
Expert Answer
Let block of mass moves down by a distance h .
Then string length JK increases by h .
Pulley P3 is moved down by distance h , hence string lengths IH and FG are increased by h .
Since string length as shown as E-F-G-H-I-J-K is constant , increases of length JK, IH and FG make string length CF to decreas by 3h .
Hence pulley P1 moves right by distance 3h and length of string AB is shortened by 3h .
Hence block of mass m1 moves by distance 3h
Hence if magnitude of displacement dx of block of mass m1 is 3 times of magnitude dy of block of mass m2
dx = 3 dy
speed of blocks are related as
dx/dt = 3 dy/dt
acceleration of blocks are related as
( d2x / dt2 ) = 3 ( d2y / dt2 )
a1 = 3 a2
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