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A particle is starting from rest and moving with constant acceleration find the ratio of distance covered in the 1st 2nd and 3rd second

Asked by Rohitparmar2332 25th June 2019, 8:46 AM
Answered by Expert
Answer:
Distance covered by the particle in nth second is given by
S subscript n equals u plus a over 2 open parentheses 2 n minus 1 close parentheses
So distance covered in 1st second
s subscript n equals 0 plus a over 2 open parentheses 2 cross times 1 minus 1 close parentheses equals a over 2
d i s tan c e space c o v e r e d space i n space 2 n d space s e c o n d
s subscript n equals 0 plus a over 2 open parentheses 2 cross times 2 minus 1 close parentheses equals fraction numerator 3 a over denominator 2 end fraction
d i s tan c e space c o v e r e d space i n space 3 r d space s e c o n d
s subscript n equals 0 plus a over 2 open parentheses 2 cross times 3 minus 1 close parentheses equals fraction numerator 5 a over denominator 2 end fraction
s subscript 1 colon s subscript 2 colon s subscript 3 equals 1 colon 3 colon 5
Answered by Expert 25th June 2019, 9:46 AM
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