A particle has a displacement of 12m towards east and 5m towards north and 6m vertically upwards. Find the magnitude of the sum of these displacements.
The resultant displacement due to 12 m towards east and 5 m towards north (which are at 90o to each other) lies in the plane of paper and is given by.
Displacement 6 m is vertically upward perpendicular to the plane of paper. Therefore, the angle between R1 and 6 m is 90º.The resultant of these to (say R2) will be
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