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CBSE Class 12-science Answered

A charged particle moving in a uniform magnetic field of induction 10-3 Wb/m2  with a velocity of 106 m/s in a circular path of radius 0.45 cm. Find out the specific charge of the particle.
Asked by Topperlearning User | 20 May, 2015, 09:59: AM
answered-by-expert Expert Answer

As we know that for circular motion of charged particle is given as,

 begin mathsize 11px style qvB equals mv squared over straight r qB equals mv over straight r The space specific space charge space of space the space particle space equals straight q over straight m equals straight v over Br space equals fraction numerator 10 to the power of 6 over denominator left parenthesis 10 to the power of negative 3 end exponent cross times 0.45 cross times 10 to the power of negative 2 end exponent right parenthesis end fraction equals fraction numerator 10 to the power of 11 over denominator 0.45 end fraction space equals 2.22 cross times 10 to the power of 11 space straight C divided by kg end style

 

Answered by | 20 May, 2015, 11:59: AM

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