CBSE Class 12-science Answered
Let a positive charge particle charge q is moving with velocity in uniform magnetic field
.
Let the angle between and
is θ.
Due to the interaction between the applied magnetic field and the magnetic field produced by the moving charge, it experiences a force, which is known as magnetic Lorentz force (). The magnitude of this force (
) is directly proportional to:
i) The magnitude of charge, F q--------(1)
ii) The component of velocity acting perpendicular to the direction of the magnetic field, F v sinθ---------(2)
iii) The magnitude of the applied magnetic field, F B---------(3)
Combining equations (1), (2) and (3)
F α qvB sinθ
F= k qvB sinθ
Where k is the constant of proportionality. Its value is found to be one i.e k=1. Therefore
F= qvB sinθ
In vector form, = q(
×
)
This is an expression for the magnetic Lorentz force.