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# A block of wood is kept on a table top . The mass of wooden block is 5kg and its dimension are 40cm*25cm*10cm. Find pressure extended

Asked by srivathchava15 14th March 2015, 9:07 PM
Given:
Mass of the wooden block= 5 kg
Dimensions = 40 cm x 25 cm x 10 cm
The weight of the wooden block applies a thrust on the top of the table.
Thrust = F = m x g
= 5 kg x 9.8 m s-2
= 49 N
Considering the sides of dimensions,
(a) 25 cm x 10 cm
(b) 40 cm x 25 cm

(a) When the block lies on its sides of dimensions 25 cm x 10 cm

Area of a side = length x breadth
= 25 cm x 10 cm = 250 cm2 = 0.025 m2
Therefore,

The pressure exerted by 25 cm x 10 cm is 1960 N m-2.

(b) When the block lies on its sides of dimensions 40 cm x 25 cm

Area of a side = length x breadth
= 40 cm x 25 cm = 1000 cm2 =  0.1m2
Therefore,

The pressure exerted by 40 cm x 25 cm is 490N m-2.
Answered by Expert 14th March 2015, 10:04 PM
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