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CBSE Class 11-science Answered

4th?
question image
Asked by smanishkumar2002 | 04 Aug, 2018, 10:51: PM
answered-by-expert Expert Answer
begin mathsize 18px style we space have space to space find space pair space of space lines space passing space through space center
Homogenizing
lx plus my equals straight n squared
fraction numerator lx plus my over denominator straight n squared end fraction equals 1
straight y squared equals ax
making space degree space same....
straight y squared equals ax open parentheses fraction numerator lx plus my over denominator straight n squared end fraction close parentheses
straight n squared straight y squared equals alx squared plus amxy
alx squared plus amxy minus straight n squared straight y squared equals 0...... pair space of space line space passing space through space center
condition space fot space them space to space be space perpendicular
coeff space of space straight x squared space plus space coeff space of space straight y squared space equals 0
al minus straight n squared equals 0
straight n squared equals al
straight a comma straight n comma straight l space are space in space GP
end style
Answered by Arun | 16 Aug, 2018, 10:47: AM

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