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CBSE Class 11-science Answered

work done
Asked by rekkakr1095 | 26 Nov, 2010, 12:58: PM
answered-by-expert Expert Answer
Work done = (1/2)mv2 - 0 = (1/2)x 10 x 100 - 0 = 500 J
 
If the object falls freely under the influence of gravity, let v' is the velocity attained by the object at height of 10 m.
 
v'2 = u2 + 2 gh = 0 + 2 x 10 x 10 = 200 units
 
Now in this case work done = (1/2)mv'2 - 0 = (1/2)x10x200 - 0 = 1000J
 
So the work done by the push of the air on the object = 1000 - 500 = 500J
 
 
Answered by | 26 Nov, 2010, 02:38: PM

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