WORD PROBLEM If zeba were younger by 5 years than what she really is, then the square of her age(in years) would have been 11 more than five times her actual age. what is her present age now????

Asked by  | 28th Feb, 2012, 09:11: AM

Expert Answer:

Let the present age of Zeba is x years.

Then, 5 years before her age would be (x – 5) years

According to the question, (x – 5)2 = 11 + 5x 

x2 + 25 -10x = 11 + 5x

x2 – 15x + 14 = 0   

x2 – 14x - x + 14 = 0

x(x – 14)-1(x-14)=0

(x-1)(x-14) = 0

x =1 or 14  

x =1 is rejected since in this case before 5 years her age would be negative which is not possible.     

So, Zeba’s present age is 14 years.

Answered by  | 28th Feb, 2012, 09:51: AM

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